FANDOM


(Blog post created or updated.)
 
(Blog post created or updated.)
 
(One intermediate revision by one user not shown)
Line 1: Line 1:
 
I stubled across 3 false proofs, see if you can find the errors.
 
I stubled across 3 false proofs, see if you can find the errors.
   
1.
+
==#1==
X=Y
+
* X=Y
X^2=X*Y
+
* X^2=X*Y
X^2-Y^2=X*Y-Y^2
+
* X^2-Y^2=X*Y-Y^2
(X+Y)*(X-Y)=Y*(X-Y)
+
* (X+Y)*(X-Y)=Y*(X-Y)
X+Y=Y
+
* X+Y=Y
2Y=Y
+
* 2Y=Y
2=1
+
*2=1
   
2.
+
==#2==
X=0.99999...
+
* X=0.99999...
10X=9.99999...
+
* 10X=9.99999...
10X-X=9.99999...-X
+
* 10X-X=9.99999...-X
9X=9
+
* 9X=9
X=1
+
*X=1
0.99999...=1
+
* 0.99999...=1
   
3.
+
==#3==
 
This one is a word problem.
 
This one is a word problem.
 
Imagine a square with sides of 4, and therefore a perimiter of 16.
 
Imagine a square with sides of 4, and therefore a perimiter of 16.
Cut corners, and the perimiter stays the same
+
Cut corners, and the perimiter stays the same. See below for a visual.
Ex.
+
----
_____ ___
 
| | equals _| |_
 
| | |_ _|
 
|_____| |___|
 
   
  +
*HHHHHHHHHH
  +
*HHHHHHHHHH
  +
*HHHHHHHHHH
  +
*HHHHHHHHHH
  +
*HHHHHHHHHH
  +
*HHHHHHHHHH
  +
  +
  +
The perimeter of the above shape is equal to the perimeter of the shape below.
  +
(_ equals negative space)
  +
  +
*____HHHH____
  +
*____HHHH____
  +
*HHHHHHHHHH
  +
*HHHHHHHHHH
  +
*____HHHH____
  +
*____HHHH____
  +
  +
----
 
Repeat to infinity.
 
Repeat to infinity.
 
Square becomes a circle
 
Square becomes a circle
16=Pi*(2)^2
+
* 16=Pi*(2)^2
 
Therefore, Pi equals 4
 
Therefore, Pi equals 4
+
----
 
That's all folks!
 
That's all folks!
   
+
''~₮iger~'' :. [[User_talk:Keo5|<small>''Talk''</small>]] ''&'' [[User:Keo5|<small>''Profile''</small>]] .:
 
[[Category:Blog posts]]
 
[[Category:Blog posts]]

Latest revision as of 23:01, December 24, 2011

I stubled across 3 false proofs, see if you can find the errors.

#1Edit

  • X=Y
  • X^2=X*Y
  • X^2-Y^2=X*Y-Y^2
  • (X+Y)*(X-Y)=Y*(X-Y)
  • X+Y=Y
  • 2Y=Y
  • 2=1

#2Edit

  • X=0.99999...
  • 10X=9.99999...
  • 10X-X=9.99999...-X
  • 9X=9
  • X=1
  • 0.99999...=1

#3Edit

This one is a word problem. Imagine a square with sides of 4, and therefore a perimiter of 16. Cut corners, and the perimiter stays the same. See below for a visual.


  • HHHHHHHHHH
  • HHHHHHHHHH
  • HHHHHHHHHH
  • HHHHHHHHHH
  • HHHHHHHHHH
  • HHHHHHHHHH


The perimeter of the above shape is equal to the perimeter of the shape below. (_ equals negative space)

  • ____HHHH____
  • ____HHHH____
  • HHHHHHHHHH
  • HHHHHHHHHH
  • ____HHHH____
  • ____HHHH____

Repeat to infinity. Square becomes a circle

  • 16=Pi*(2)^2

Therefore, Pi equals 4


That's all folks!

~₮iger~ :. Talk & Profile .:

Community content is available under CC-BY-SA unless otherwise noted.